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LoadCairn / Rack power

Rack power & PDU capacity calculator

Compare an expected rack load with a PDU’s estimated real-power capacity. See the calculation and change each assumption in your browser; valid estimates can be saved to a LoadCairn Pro project.

PDU and rack inputs

Illustrative example · editable

Starting values are illustrative and editable: 5,000 W, 208 V line-to-line, 30 A per line, balanced three-phase, 0.90 power factor, and an 80% planning cap. They do not describe a specific PDU.

Enter expected rack real power. A zero-watt load is valid.

For three phase, enter line-to-line voltage; for single phase, enter voltage across the load.

Use the PDU nameplate current per line, not a sum across lines.

Use a measured or manufacturer-specified value when available.

An editable planning assumption, not a universal code rule or device guarantee.

Electrical phase

Three-phase uses line-to-line voltage and current per line, and assumes balanced loading. For single phase, use voltage across the load and its line current.

Unsaved · Calculated in your browser

Live planning estimate

Planning-limited capacity

7,782 W
Rack load is within the selected planning cap. Rounded for display; calculations retain full precision.
Checking Pro access…Download rack power reportExport CSV

Estimates for planning only, not a substitute for a licensed engineer’s design or manufacturer data.

Rack load
5,000 W
Apparent capacity
10,808 VA
Nominal real-power capacity
9,727 W
Nominal utilization
51.4%
Planning-cap utilization
64.3%
Remaining PDU capacity (planning guidance)
2,782 W
Calculation details

Inputs used

Rack real-power load
5000 W
PDU voltage (line-to-line)
208 V
Rated current per line
30 A
Selected phase
balanced three-phase
Power factor
0.9
Planning cap
80%

Formula and live derivation

Apparent capacity (VA) = √3 × V(line-to-line) × A(line) [balanced three phase]
Nominal real-power capacity (W) = apparent capacity × power factor
Planning capacity (W) = nominal real-power capacity × (planning cap % ÷ 100)
Utilization (%) = rack load (W) ÷ capacity (W) × 100; remaining planning headroom (W) = planning capacity − rack load

balanced three-phase: √3 × 208 V × 30 A = 10,808 VA

10,808 VA × 0.9 PF = 9,727 W nominal

9,727 W × 80% = 7,782 W planning capacity

5000 W ÷ 9,727 W = 51.4% nominal utilization

5000 W ÷ 7,782 W = 64.3% planning-cap utilization

7,782 W − 5000 W = 2,782 W planning headroom

Calculations retain full precision; displayed values are rounded for readability.

Assumptions

  • The three-phase estimate assumes balanced loading across the phases. The single-phase estimate uses one line voltage and one line current.
  • The entered power factor is applied to apparent capacity to estimate real-power capacity. Use a value appropriate to the equipment and measurement conditions.
  • The entered planning cap is applied to nominal real-power capacity; 80% is only the editable starting assumption shown here.

Sources

Worked example

The editable starting example uses a 5,000 W load and a hypothetical balanced three-phase PDU input of 208 V line-to-line, 30 A per line, and 0.90 power factor. The 80% planning cap is an assumption for illustration, not a rating or universal electrical rule.

√3 × 208 V × 30 A = 10,808 VA

10,808 VA × 0.90 = 9,727 W nominal

9,727 W × 80% = 7,782 W planning capacity

5,000 W ÷ 9,727 W = 51.4% nominal utilization

5,000 W ÷ 7,782 W = 64.3% planning-cap utilization

7,782 W − 5,000 W = 2,782 W planning headroom

Limitations

Not evaluated

  • Does not check individual phase loading, branch circuits, breakers, receptacles, or outlet limits.
  • Does not evaluate A/B-feed redundancy, transfer behavior, inrush or transient load, voltage drop, conductor sizing, or protective-device coordination.
  • Does not apply environmental or installation derating, validate equipment compatibility, or determine local-code requirements.
  • Does not confirm the PDU input rating, usable outlet capacity, or a device-specific continuous-load limit. Read the selected unit’s current manufacturer documentation and nameplate.
  • Power factor can vary with load and waveform. Nonlinear loads, harmonics, and unbalanced systems need equipment-specific analysis.

LoadCairn / Rack power guide

Rack power density: definition, formula, and planning limits.

Rack power density is a compact way to describe how much IT power a rack is expected to draw. This guide connects the kW-per-rack idea to PDU capacity, shows a first-pass example, and makes clear what an early planning estimate cannot decide for you.

At a glance

Units / planning only

Rack power density (kW/rack) = rack IT load (kW) ÷ rack count

1 kW = 1,000 W

Planning capacity = nominal real-power capacity × planning cap

For a single rack, the rack count is one, so a 5,000 W load is 5 kW/rack. For a row or room, use a consistent load basis and divide the total by the number of racks being planned. Average density does not describe the highest-load rack.

01 / The metric

What rack power density means

Rack power density is the expected electrical demand assigned to one rack, usually expressed in kilowatts per rack (kW/rack). It is not the PDU nameplate rating and it is not the same as the total facility power. It describes the IT load that a rack, row, or room is expected to carry.

The number is useful because electrical distribution and heat rejection both respond to the load in the rack. A planning team can use it to compare a proposed rack layout with available PDU capacity, identify unevenly loaded racks, and start a discussion about cooling distribution. It should remain tied to a defined load basis and time horizon.

Density is a planning descriptor, not a promise that every rack can safely operate at that value. Check actual equipment, circuits, cooling, redundancy, environmental limits, and applicable requirements before committing a design.

02 / Units and formula

Start with kW, then check the feed

Convert watts to kilowatts by dividing by 1,000. Divide the total IT load by the number of racks in the planning group. Keep the numerator and rack count on the same basis: measured demand with measured racks, or modeled peak demand with modeled racks.

Rack density = total rack load (W) ÷ 1,000 ÷ rack count

Rack density = total rack load (kW) ÷ rack count

Density alone does not answer whether a PDU can supply the load. For that check, the calculator estimates apparent capacity first, then applies power factor and a planning cap:

Apparent capacity (VA) = V × A for single phase

Apparent capacity (VA) = √3 × V × A for balanced three phase

Nominal real-power capacity (W) = apparent capacity × power factor

Planning capacity (W) = nominal real-power capacity × cap ÷ 100

For three phase, use line-to-line voltage and current per line. The three-phase equation assumes balanced loading. For single phase, use the voltage across the load and its line current.

03 / Practical planning

What to bring to a first pass

The existing calculator keeps the electrical assumptions editable so you can test a proposal rather than treating one default as a specification.

Rack IT load
The expected real-power load for the rack, entered in watts (W).
PDU voltage
Use voltage across the load for single phase, or line-to-line voltage for balanced three phase.
Current per line
Use the PDU nameplate current per line, not a sum across phases.
Power factor
A value from greater than 0 through 1 that converts apparent capacity to estimated real-power capacity.
Planning cap
A percentage applied to nominal real-power capacity to leave planning headroom. The calculator starts at 80%.

04 / Worked example

Read the density and the headroom together

The following values match the calculator's illustrative starting inputs. They are sample arithmetic, not a recommendation for a particular rack or PDU.

Illustrative example · not a design value

Rack load = 5,000 W = 5.0 kW

One rack: 5.0 kW ÷ 1 rack = 5.0 kW/rack

Three phase: √3 × 208 V × 30 A ≈ 10,808 VA

Nominal real-power capacity ≈ 10,808 VA × 0.90 = 9,727 W

80% planning capacity ≈ 9,727 W × 0.80 = 7,782 W

Planning headroom ≈ 7,782 W − 5,000 W = 2,782 W

In this example, 5.0 kW/rack describes the rack load, while about 7.8 kW describes the selected planning capacity for the illustrative PDU inputs. Those are different quantities: density describes demand; the capacity check tests whether the assumed feed has room under the chosen cap.

05 / Use it carefully

Useful questions for early planning

06 / Explicit limits

Where this estimate stops

The calculator is a transparent early-planning aid. It does not certify an installation as safe, compliant, or suitable, and it does not replace equipment documentation or a qualified review.

07 / Further reading

Electrical context

These references provide context for the simplified equations and why PDU model details still matter.

08 / Run an estimate

Check a rack against PDU capacity

Enter your own load, voltage, phase, current, power factor, and planning cap to see the calculation trace and the remaining planning headroom.